KHC2O4 + NaOH ==> NaKC2O4 + H2O
mols KHC2O4 = grams/molar mass = ?
mols NaOH = mols KHC2O4(see the coefficients in the balanced equation).
Then M NaOH = mols NaOH/L NaOH and solve for M
A sample of potassium hydrogen oxalate, KHC204, weighing 0.717 g, was dissolved in water and titrated with 18.47 mL of an NaOH solution. Calculate the molarity of the NaOH solution.
1 answer