Molecular weight of glucose is 180.16 g/mo and its formula is C6H1206.
a.) 2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(12 moles of H/6 moles of C)*(6.02x10^23 atoms/mole of H)=atoms of H
****Notice that Avogadro's number cancels out
b.) 2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(1 mole of glucose/12 moles of C)*(6.02 x 10^23 atoms/1mole of glucose)= molecules of glucose
****Notice that Avogadro's number cancels out
c.)2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(1 mole of glucose/12 moles of C)= moles of glucose
d.2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(1 mole of glucose/12 moles of C)*(180.16 g/mole)= glucose in grams
a sample of glucose, c6h12o6 contains 2.03*10^21 atoms of carbon.
(a)how many atoms of hydrogen does it contain?
(b)how many molecules of glucose does it contain?
(c)how many moles of glucose does it contain?
(d)what is the mass of this sample in grams?
its kinda long, but i would appreciate it if someone would guide me through it
thank you:)
6 answers
Thank you soooooooooooo much!!!
On problem C, why is the mole for Carbon 12 and not 6. Isn't the mole of H 12?
Setup is correct, but in parts b, c, and d, it should be 6 moles of carbon because the formula is C6H12O6, NOT C12H12O6
Not sure if I did this right didn’t understand but for
A. I got 5.02 x 100^22
B.6.02x10^23 C.083
D.180.16g
can someone please explain it to me
A. I got 5.02 x 100^22
B.6.02x10^23 C.083
D.180.16g
can someone please explain it to me
To make this easier. The ratio of carbon to hydrogen is 1/2 so for part a you have to multiply it by 2 so the answer would be 4.06 x 10^22.
For part b, you would have to find the molar mass of glucose which is 180.16 and multiply it by 6.023 x 10^23 so the answer would be 1.085 x 10^26. For c, you would divide the number found in part b by 6.023 x 10^23, and in part d it is the molar mass of glucose. Hope this helps
For part b, you would have to find the molar mass of glucose which is 180.16 and multiply it by 6.023 x 10^23 so the answer would be 1.085 x 10^26. For c, you would divide the number found in part b by 6.023 x 10^23, and in part d it is the molar mass of glucose. Hope this helps