A rotten cranberry will lose at least 90% of its total energy during a bounce. If the cranberries are dropped from a height of 10 cm, what is the minimum height in cm of the wall so that no rotten cranberries could ever bounce over it?

Answer 1

ANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH
K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM
0+0.5MVSQUARE=M(9.81)(0.1)
V=1.400 MASS M/SEC
90% LOSE OF ENERGY
M.E=MASS(G)(H) @ THE TOP
M.E=MASS (9.81)(0.1)
M.E=MASS 0.981
REDUCTION OF 90% DURING BOUNCE
M.E= MASS 0.981-MASS 0.981(0.9)
M.E= MASS 0.0981
MASS 0.0981=MASS (9.81)(H)
H=0.01M OR 1CM

edsel salariosa

Answer 2

ANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH
K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM
0+0.5MassVSQUARE=Mass(9.81)(0.1)+0
V=1.400 MASS M/SEC
90% LOSE OF ENERGY
M.E=MASS(G)(H) @ THE TOP
M.E=MASS (9.81)(0.1)
M.E=MASS 0.981
REDUCTION OF 90% DURING BOUNCE
M.E= MASS 0.981-MASS 0.981(0.9)
M.E= MASS 0.0981
MASS 0.0981=MASS (9.81)(H)
H=0.01M OR 1CM
since the mass of a object doesn't given you can cancel both side of the equation and you can find the height

edsel salariosa
research and development engineer

Answer 3

The total energy of the cranberry when it bounces is the same as the initial gravitational potential energy since we can neglect air resistance. Therefore the total energy is mg(10~\mbox{cm})mg(10 cm). After bouncing, the total energy is at most (0.1)mg(10~\mbox{cm})(0.1)mg(10 cm). Therefore the maximum height a rotten cranberry can bounce up is 1~\mbox{cm}1 cm, and if we set our wall at that height no berries can bounce over.