EDSEL

ANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM 0+0.5MVSQUARE=M(9.81)(0.1) V=1.400 MASS M/SEC 90% LOSE OF ENERGY M.E=MASS(G)(H) @ THE TOP M.E=MASS (9.81)(0.1) M.E=MASS 0.981 RED...

ANSWER IS 1CM. SOLUTION TOTAL MECHANICAL ENERGY= TO K.E+P.E =0.5MASS VSQUARE+MASS GH K.E TOP +P.E TOP= K.E BOTTOM +P.E BOTTOM 0+0.5MassVSQUARE=Mass(9.81)(0.1)+0 V=1.400 MASS M/SEC 90% LOSE OF ENERGY M.E=MASS(G)(H) @ THE TOP M.E=MASS (9.81)(0.1) M.E=MASS 0...

H=0.5 GT^2+Vyt Vx=d/t g=9.81m/sec a. Vx=0.3 d=0.15 0.3=0.15/t t=2secs H=0.5(9.81)(2)^2+0 H=19.62m b. 0.6=d/2 d=1.2m

1kg=9.81newton 75kg(9.81)=735.75newton tension stess= p/a 1.25kn/cm^2=0.73575kn/a a=1.6989 cm^2 a=3.1415/4(d^2) 1.6989=3.1415/4(d^2) d=1.471 cm edsel salariosa research and development engineer

1st bounce=0.2(4/5)=0.16m 2nd bounce=0.16(4/5)=0.128m or 128cm