Efficiency η = W/Q = 1/6,
If T1 is the temperature of the source,
and T2 is the temperature of the sink,
η = (T1-T2)/T1 = 1- T2/T1
η = 1/6 = 1- T2/T1
2 η = 2/6 = (T1-(T2- 62))/T1 =1- (T2-62)/T1,
2/6 -1/6 = 1-(T2-62)/T1 – 1 - T2/T1.
1/6 = 62/T1
T1 = 372 K.
T2/T1 =1 – 1/6 = 5/6.
T2 = (5/6) •T1 = 310 K
A reversible engine converts 1/6 of the heat input into work. When the temperature of the sink is reduced by 62C, the efficiency of the engine is doubled.What are the temperarure of the source and sink?
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