Asked by Jon
A reversible heat engine operates between thermal reservoirs at 1000 K and 290 K. If 8610 J is extracted from the hot reservoir, how much work is done by the heat engine?
Answers
Answered by
bobpursley
8610 (1000-290)/1000= what
Answered by
Mrs.Smooch
ç = 1 - 290K/1000K = 0.29 = 29.0%
The thermal efficiency is defined as the amount of work done per amount of heat absorbed from hot reservoir or...
ç = W/Qh
so then you would just use
W = e*Qh
and plug in what you know
The thermal efficiency is defined as the amount of work done per amount of heat absorbed from hot reservoir or...
ç = W/Qh
so then you would just use
W = e*Qh
and plug in what you know
Answered by
bobpursley
Hannah, reread the question. My response is correct. It does not ask for thermalefficiency.
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