Question

A reversible heat engine operates with an efficiency of 50%. If during each cycle it rejects 150 cal to a reservoir of heat at 30°C, then what is the temperature of the other reservoir and how much work does it carry out per cycle?
bobpursley
.5=(tin-tout)/tin
where tout is (30+273) , solve for tin (temp of original reservoir)

work per cycle=300cal (to get 50 percent efficiency)

Related Questions

A heat engine absorbs 126 kcal of heat and exhausts 77 kcal of heat in each cycle. Calculate the ef... An ideal gas heat engine operates in a Carnot Cycle between temperatures of 266 and 115°C. It abso... a carnot heat engine operates between reservoirs at 550K and 300K, discarding 1500J of heat in each...