Asked by Samuel
A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle's diagonal measurement is 46 inches, find the height.
Answers
Answered by
MathGuru
Use the Pythagorean theorem:
a^2 + b^2 = c^2
x = height
x + 7 = width
Therefore:
x^2 + (x + 7)^2 = 46^2
Expand and try to factor. If this does not factor easily, use the quadratic formula to solve.
a^2 + b^2 = c^2
x = height
x + 7 = width
Therefore:
x^2 + (x + 7)^2 = 46^2
Expand and try to factor. If this does not factor easily, use the quadratic formula to solve.
Answered by
charys
A rectangle is drawn so the width is 3 inches longer than the height. If the rectangle's diagonal measurement is 55 inches, find the height.
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