P = 2L + 2W
62 = 2(W + 7) + 2W
62 = 4W + 14
48 = 4w
12 = W
62 = 2(W + 7) + 2W
62 = 4W + 14
48 = 4w
12 = W
W=12
According to the given information, the length of the rectangle is 7 inches longer than the width, so the length would be x + 7 inches.
The perimeter of a rectangle is given by the formula: perimeter = 2(length + width).
Substituting the given values, we have: 62 = 2(x + 7 + x).
Simplifying the equation, we get: 62 = 2(2x + 7).
Expanding and simplifying further, we have: 62 = 4x + 14.
Subtracting 14 from both sides of the equation, we get: 48 = 4x.
Dividing both sides by 4, we find that x = 12.
Therefore, the width of the rectangle is 12 inches and the length is 12 + 7 = 19 inches.
Let's assume the width of the rectangle is "w" inches.
According to the problem, the length of the rectangle is 7 inches longer than the width. So, the length would be "w + 7" inches.
The formula for calculating the perimeter of a rectangle is:
Perimeter = 2(length + width)
Substituting the values from the problem into the formula:
62 = 2(w + 7 + w)
Now, we can simplify the equation and solve for "w":
62 = 2(2w + 7)
62 = 4w + 14
4w = 62 - 14
4w = 48
w = 48/4
w = 12
So, the width of the rectangle is 12 inches.
To find the length, we can substitute the value of "w" into the expression "w + 7":
Length = 12 + 7
Length = 19
Therefore, the length of the rectangle is 19 inches and the width is 12 inches.