For:
Assume all values are in inches.
L=length of rectangle
W=width of rectangle
P=perimeter of rectangle
P=L + W + L + W
The problem states:
P=78
L=W + 3
Substitute the above values into the perimeter equation.
Set up an equation involving only W, the width of the rectangle.
Assume all values are in inches.
L=length of rectangle
W=width of rectangle
P=perimeter of rectangle
P=L + W + L + W
The problem states:
P=78
L=W + 3
Substitute the above values into the perimeter equation.
According to the problem, the length of the rectangle is 3 inches longer than the width. So, the length can be expressed as W + 3.
Now, let's recall the formula for the perimeter of a rectangle: Perimeter = 2(Length + Width)
We are given that the perimeter of the rectangle is 78. Substituting the expressions for length and width into the formula, we get:
78 = 2(W + 3 + W)
Simplifying the equation, we have:
78 = 2(2W + 3)
Now, we can solve this equation to find the value of W, which represents the width of the rectangle.