A = lw
35 = 5 * 7
A rectangle has a perimeter of 24 and an area of 35 square feet. What is the length and width of the rectangle?
2 answers
length --- x
width ---- y
2x + 2y = 24
x + y = 12
y = 12-x
xy=35
x(12-x) = 35
-x^2 + 12x - 35 = 0
x^2 - 12x + 35 = 0
(x-7)(x-5)= 0
x = 7 or x = 5
if x=7, y=5 or if x=5, then y=7
the rectangle is 5 by 7
width ---- y
2x + 2y = 24
x + y = 12
y = 12-x
xy=35
x(12-x) = 35
-x^2 + 12x - 35 = 0
x^2 - 12x + 35 = 0
(x-7)(x-5)= 0
x = 7 or x = 5
if x=7, y=5 or if x=5, then y=7
the rectangle is 5 by 7
9 answers