A recent poll conducted by Gallup Inc. asked the following question:

In general, how much trust and confidence to you have in the mass media - such as newspapers, TV, and radio - when it comes to reporting the news fully, accurately, and fairly? A great deal, a fair amount, not very much, or non at all?

58% of respondents has a negative view of the media, meaning they responded with either not very much or non at all.

Two people are randomly chosen, each is asked the poll question above. What is the probability?

Two people are randomly chosen, each is asked the poll question above. What is the probability

Part (a) that both have a negative view of mass media?
Part (b) neither have a negative view of the mass media?
Part (c) at least one of the two has a negative view towards the media?

3 answers

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

(a) .58 * .58

(b) .42 * .42

(c) "at least one" = one or two

P(2) = (a)

P(1) = .58 * .42

Either-or probabilities are found by adding the individual probabilities.
C) should me 1 - b
hi so how exactly did you figure out C