A projectile fired upward from ground level is to reach a maximum height of 1,600 feet. What is its initial velocity?

Answer 1

Given:
s(t) = 1600
v(t) = 0
Let s(0) = 0
First find: t, in terms of v(0)
Using: s(t) = v(0)t-(1/2)gt^2

Then substitute for t to find v(0)
Using: v(t) = v(0) - gt