If a projectile is fired straight upward from the ground with an inital speed of 96 feet per second, then its height (h) in feet after t seconds is given by the equation

Question

h(t)=-16t^2+96t

Find the maximum height of the projectile.

Answer 1

Tr = (V-Vo)/g.
Tr = (0-960 / -32 = 3 s. = Rise time.

h(t) = -16*3^3 + 96*3 = 144 Ft.