t seconds from the time of observation, the truck has gone
110km/hr * 1hr/3600s * 1000m/km * t s= 30.55t m
cop car has accelerated at
44.44 m/s / 20s = 2.22 m/s^2
so its distance is
1.11 * 20^2 + (44.44(t-30))
so set them equal, and you find that the cop caught up after 64 seconds.
In that time, the truck has gone
160 * 64/3600 = 2.844 km
A police car observes a truck traveling a 110kmph. The police car starts pursuit 30secs after the observation, accelerate to 160kmph in 20secs. Assuming the speeds are maintained const on a straight road, how far from the observation point, will the chase end?
1 answer