A speeder passes a police car while traveling 130km/h. the police car imediently starts to accelerate at 10m/s^2 until the police car catches up to the speeder. how long does it take the police car to catch up?

Answer 1

First, convert the speed to m/s

Vcar = 130 km/h = 36.11 m/s

Solve for t:

36.11*t = (a/2) t^2 = 5 t^2

where a is the acceleration rate of the poice car.

Ignore the t=0 solution. Take the other one.