a speeder with unknown velocity passes a police car.the policr car starts to accelerate at a rate of2.2 m/s/s in the direction of the speeder as soon as the speeder passes.the police car reaches the same velocity as the speeder after he travelled 715 m. What is the velocity of the speeder

Answer 1

The velocity attaned by the police car after traveling X = 715 m is

V = sqrt(2aX) = 56.1 m/s
= 202 km/h = 125.5 mph

That must also be the speeder's velocity, since the speeder is not accelerating.

Answer 2

A speeder passes a parked police car at a
constant speed of 150 m/s. At that instant,
the police car starts from rest with a uniform
acceleration of 10 m/s
2
.
How much time passes before the speeder
is overtaken by the police car?
Answer in units of s