Question

a speeder is going at a constant speed of 20m/s when a police car accelerates from rest at a rate of 4.5,/ssquared to catch them. How long did it take for the officer to reach the speeding car?

Answer 1

distanceS=20*t
distanceP=1/2 *4.5*t^2
the distances traveled are the same, set them equal, and solve for t.