Asked by Sam
a speeder is going at a constant speed of 20m/s when a police car accelerates from rest at a rate of 4.5,/ssquared to catch them. How long did it take for the officer to reach the speeding car?
Answers
Answered by
bobpursley
distanceS=20*t
distanceP=1/2 *4.5*t^2
the distances traveled are the same, set them equal, and solve for t.
distanceP=1/2 *4.5*t^2
the distances traveled are the same, set them equal, and solve for t.
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