Question

A speeder doing 50.0 mi/hr (about 22 m/s) in a 25 mi/hr zone approaches a parked police car. The instant the speeder passes the police car, the police begin their pursuit. If the speeder maintains a constant velocity, and the police car accelerates with a constant acceleration of 4.50 m/s^2, (a) how long does it take for the police car to catch the speeder, (b) how far have the two cars traveled in this time, and (c) what is the velocity of the police car when it catches the speeder?

Answer 1

Now this is very similar but easier than the one you threw up from the roof of the building. You try it. I have grand kids playing hockey now.

Answer 2

I figured it out. i juss had to find the T to help me solve the other parts

Answer 3

i cant seem to get this question though .

120 grams of an unknown metal at a temperature of 95 degrees celcuius is poured into 140 grams of aluminum calorimeter containing 220 grams of water. If the inital temperature of the water and calorimeter was 15 degree celcuius and the final temperature was 18 celcius, find the specfic heat of metal. the specfic heat of aluminum is .22 calories/gams Celcius. The specfic heat of water is 1.00 calorie /gram Celcius

Answer 4

Vs = 50mi/h * 1600m/mi * 1h/3600s = 22.22 m/s. = Velocity of the speedster.

a. Ds = Dp
22.2*t = 0.5a*t^2
Divide both sides by t:
0.5a*t = 22.2
0.5*0.450t = 22.2
0.225t = 22.2
t = 98.8 s.

b. Ds = Dp = 22.2*t = 22.2 * 98.8 = 2193 m.

c. V^2 = Vo^2 + 2a*d

Vo = 0
a = 0.450 m/s^2
d = 2193 m.
Solve for V.