HOW TO:
formula: ΔX=Vi(t)+ 1/2(a)(t^2)
what we know:
Vi= 45.0 m/s
t= .700 s
a= 3.00 m/s^2
NOW PLUG IN:
ΔX=45(.7)+1/2(3)(.7^2)
ΔX= 32.235 m
A police car is traveling at a velocity of 15.0 m/s due north, when a car zooms by at a constant velocity of 45.0 m/s due north. After a reaction time 0.700 s the policeman begins to pursue the speeder with an acceleration of 3.00 m/s^2. Including the reaction time, how long does it take for the police car to catch up with the speeder?
2 answers
it's supposed to be time, not distance as answer
1 answer