A police car is traveling at a velocity of 19.0 m/s due north, when a car zooms by at a constant velocity of 49.0 m/s due north. After a reaction time 0.600 s the policeman begins to pursue the speeder with an acceleration of 6.00 m/s^2. Including the reaction time, how long does it take for the police car to catch up with the speeder?

Answer 1

19t + 0.5a*t^2 = 49t + 49*0.6
19t + 0.5*6*t^2 = 49t + 29.4
3t^2 - 30t - 29.4 = 0
t = 10.9 s.