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Willow Newman
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A speeder passes a parked police car at a constant speed of 25.1 m/s. At that instant,the police car starts from rest with a
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a) 13.2 13.2^2=6.6^2+2(4.95)(ΔX) 174.24= 43.56+9.9ΔX 130.68=9.9ΔX ΔX=13.2
a) 13.2 13.2^2=6.6^2+2(4.95)(ΔX) 174.24= 43.56+9.9ΔX 130.68=9.9ΔX ΔX=13.2 b)6.6+13.2/2=13.2/t 9.9=13.2/t t= 1.33
HOW TO: formula: ΔX=Vi(t)+ 1/2(a)(t^2) what we know: Vi= 45.0 m/s t= .700 s a= 3.00 m/s^2 NOW PLUG IN: ΔX=45(.7)+1/2(3)(.7^2) ΔX= 32.235 m
