a particle starts from rest and moves along a straight line with an acceleration equal to 24-15√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle return to the starting point?

Question

help please thank you :-)

Answer 1

d=0=1/2 a t^2=12t^2-7.5t^3/2
t^2(12-7.5sqrtt)=0
sqrtt=12/7.5
t= that squared.

check my thinking