a particle starts from rest and moves along a straight line with an acceleration equal to 24-15√t where distance and time are measured in terms of feet and seconds respectively. with what acceleration will the particle return to the starting point?

Answer 1

a = 24-15√t
v = 24t-10t^(3/2)
s = 12t^2 - 4t^(5/2)
s=0 when 12-4√t = 0, or t=9

a(9) = 24-15√9 = -21