v = 2 + 3t
when does v=14?
now take the integral to get the distance
A particle moves with a fixed acceleration of 3 m/s^2. If its initial velocity is v(0)= 2 m/s, and its initial displacement is s(0)= 0
A)Find its velocity function v(t)
B)How long does it take for the particle to reach the velocity 14 m/s?
C)Find the distance traveled when its velocity reaches 14 m/s.
3 answers
Thank you so just to clarify for a) all you did was take the integral of the acceleration to get your v(t) function.
Then for b) do you set v=2+3t equal to 14?
c)You just take the integral of v(t) to get position function I think.
Then for b) do you set v=2+3t equal to 14?
c)You just take the integral of v(t) to get position function I think.
Yes.
The integral of the acceleration vector is the velocity vector. The constant of integration is determined by a known velocity, often the initial velocity.
The integral of velocity is displacement. Constant of integration is determined by initial position (zero here) to give position as a function of time.
The integral of the acceleration vector is the velocity vector. The constant of integration is determined by a known velocity, often the initial velocity.
The integral of velocity is displacement. Constant of integration is determined by initial position (zero here) to give position as a function of time.
1 answer