A body starts with an initial velocity of 10m/s and moves along a straight line with a constant acceleration. When the velocity of the particle becomes 50 m/s the acceleration is reversed in direction without changing magnitude. Find the velocity of the particle when it reaches the starting point.

Answer 1

position when it hits 50m/s:

vf^2=vi^2+2ad
50^2=10^2+2*a*d solve for a*d.

Now, the reverse trip:
vf^2=50^2 -2ad put the above in, and viola,

vf^2=50^2-50^2+10^2=10^2
vf=10
Think that out in your mind.

Answer 2

-70m/s^2