x'' = mu/x^2 ------>
x'' x' = mu x'/x^2 ----->
1/2 x'^2 = -mu/x + k ------>
x'^2 = -2 mu/x + const.
x'(x = c) = 0 -------->
const. = 2 mu/c --------->
x' = sqrt[2 mu/c - 2 mu/x]
A particle moves from rest, its initial position being given by x = c with reference to a fixed point O. Its acceleration at a distance ‘x’ from 0 is mu/x^2 away from O. Show that its velocity is sqrt mu/c when it is a distance ‘x’ from O.
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