Since the max of sin(anything) is +1 and the minimum is -1
v has a max of 4 -(-8) or 12 and a min of 4 - 8(1) or -4, so
-4 ≤ v ≤ 12
A particle moves along a straight line with a velocity, v m s-1, given by v =4-8sin2t, where t is the time in seconds after passing a fixed point O. Determine the range of values of v
1 answer
1 answer