s = t^3-3t^2-8t+c
use s(1) = 10 to find c,
then evaluate s(2)
A particle moves on a straight line. The velocity after t seconds is given by V= 3t^2 – 6t – 8.
The distance of the particle from the origin after one second is 1o meters. Calculate the distance of the particle from the origin after 2 seconds.
1 answer
1 answer