A motorcycle accelerates uniformly from rest and reaches a linear speed of 22.0 m/s in a time of 9.00s. The radius of each tire is 0.280m. What is the magnitude of the angular acceleration if each tire?

Answer 1

Cir. = pi * 2r = 3.14 * 0.56 = 1.76 m.
Va = 22m/s * 6.28rad/1.76m = 78.5 rad/s.

V = Vo + a*t = 78.5.
0 + a*9 = 78.5,
a = 8.72 rad/s^2.