A motorcycle accelerates uniformly from rest and reaches a linear speed of 33.4 m/s in a time of 11.6 s. The radius of each tire is 0.265 m. What is the magnitude of the angular acceleration of each tire?

Answer 1

Circumference=pi*2r = 3.14 * 0.53=1.665
m.

Va = 33.4m/s * 6.28rad/1.665m=126 rad/s

a=(V-Vo)/t = (126-0)/11.6=10.87 rad/s^2.