A model rocket is launched from rest with an upward acceleration of 6.30 m/s2 and, due to a strong wind, a horizontal acceleration of 1.50 m/s2.

Question

How far is the rocket from the launch pad 5.30 s later when the rocket engine runs out of fuel?

Answer 1

VERTICAL PROBLEM:
y = (1/2) 6.3 t^2
= 3.15 (5.3)^2

HORIZONTAL PROBLEM:
x = (1/2)1.5 t^2
= .75 (5.3)^2

d = sqrt(x^2+y^2)