A model rocket is launched from rest with an upward acceleration of 5.50 m/s^2 and, due to a strong wind, a horizontal acceleration of 1.50m/s^2 . How far is the rocket from the launch pad 7.20 later when the rocket engine runs out of fuel?

Answer 1

t = 7.2 Minutess?
t = 7.2min * 60s/min = 432 s.

X = Hor = 1.50 m/s^2.
Y = Ver. = 5.5 m/s^2.
R = Resultant acceleration.

R^2 = X^2 + Y^2. 1.5^2 + 5.5^2 = 32.5
R = 5.7 m/s^2.

d = Vo*t + 0.5a*t^2
d = 0 + 2.85*(432)^2 = 531,878 m.