A mixture of nitrogen and argon gas is compressed from a volume of 70.0 L to a volume of 61.0 L, while the pressure is held constant at 14.0 atm. Calculate the work done on the gas mixture.

Question

22 kJ

13 kJ

-13 kJ

-22 k

Answer 1

To calculate the work done on a gas mixture, we can use the formula:

Work = -PΔV

Where:
- Work is the work done on the gas mixture (in joules, J)
- P is the constant pressure (in atmospheres, atm)
- ΔV is the change in volume (in liters, L)

In this case, the pressure is constant at 14.0 atm, and the change in volume is from 70.0 L to 61.0 L.

Using the formula, we can calculate the work done:

Work = -14.0 atm * (61.0 L - 70.0 L)
Work = -14.0 atm * (-9.0 L)
Work = 126.0 atm*L

Since the units of atm*L are not in joules, we need to convert them. 1 atm*L = 101.325 J

Work = 126.0 atm*L * 101.325 J/atm*L
Work ≈ 12773.65 J

Rounded to the nearest kilojoule, the work done on the gas mixture is approximately 13 kJ.

Therefore, the correct answer is 13 kJ.