A mixture of nitrogen and argon gas is compressed from a volume of 70.0 L to a volume of 61.0 L, while the pressure is held constant at 14.0 atm. Calculate the work done on the gas mixture. Provide your answer is kJ

Answer 1

To calculate the work done on the gas mixture, we can use the equation:

Work = -PΔV

where P is the pressure and ΔV is the change in volume.

Given:
Initial volume (V1) = 70.0 L
Final volume (V2) = 61.0 L
Pressure (P) = 14.0 atm

To calculate the change in volume, we use the formula:

ΔV = V2 - V1

ΔV = 61.0 L - 70.0 L
ΔV = -9.0 L

Note: The negative sign indicates a decrease in volume.

Now, we can substitute the given values into the equation:

Work = -PΔV
Work = -14.0 atm (-9.0 L)
Work = 126.0 L⋅atm

To convert L⋅atm to kJ, we need to use the conversion factor 101.3 J = 1 L⋅atm:

Work = 126.0 L⋅atm x (101.3 J / 1 L⋅atm) x (1 kJ / 1000 J)
Work = 12,752.2 kJ

Therefore, the work done on the gas mixture is 12,752.2 kJ.