A mixture of nitrogen and argon gas is compressed from a volume of 70.0 L to a volume of 61.0 L, while the pressure is held constant at 14.0 atm. Calculate the work done on the gas mixture

Answer 1

To calculate the work done on the gas mixture, we can use the formula:

Work = -PΔV

Where P is the constant pressure and ΔV is the change in volume.

In this case, the initial volume (V1) is 70.0 L and the final volume (V2) is 61.0 L. The pressure (P) is 14.0 atm.

ΔV = V2 - V1 = 61.0 L - 70.0 L = -9.0 L (negative because the volume decreases)

Now we can calculate the work:

Work = -PΔV = -(14.0 atm)(-9.0 L) = 126.0 atm⋅L

Therefore, the work done on the gas mixture is 126.0 atm⋅L.