A metal block of density 900kg/m3 weighs 60N in air . Find its weight when immersed in paraffin wax of density 800kg/m3

Answer 1

(800/900) * 60N = 53.33 N. = Wt. lost,
Wt. in wax = Wt. in air - Wt. lost = 60 - 53.33 =

Answer 2

a piece of metal 9000 kgm weighs 70 N in air. calculate it's weight when fully immersed in a paraffin wax of density 800 kgm3

Answer 3

Please solve it

Answer 4

(800/9000)

=0.088

=0.088*70

=6.16N

wt loss

= wt in air

= wt in wax

= wt in air - wt.loss

= 70-6.16

= 63.84

Answer 5

A lump of paraffin wax with a piece of iron embedded in it weighs 1.5N in air and 0.43N when completely immersed in water.calculate the weight of the iron in the lump where density of iron is 7.00gcm3 density of wax is 0.95gcm3 density of water is 1.00gcm3
Please calculate it for me

Answer 6

2xt

Answer 7

Density of wax and iron=0.95-7.0=7.95g/cm
Upthrust=air -water
1.51N-0.43N=1.08N
Mass of fluid=1.08÷10=0.108kg
Volume of paraffin and iron=0.108÷7.95=0.0135
Mass of iron =0.0945=9.45*10^-2kg

Answer 8

A body weighs 0.20N in air, 0.12N when fully immersed in water and 0.25 N when ‘fully ‘immersed in liquid. Calculate ( i) It lost weight (ii) it relative density
Help Me out

Answer 9

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