a piece of metal of density

Question

7800kgm-3 weighs 20N in air. Cal. The
apparent weight of th metal when
completely immersed in a liquid of density 830kgm-3

Answer 1

20 N = 9.81 * m
m = 2.04 kg

volume = 2.04 kg/7800 kg/m^3
= .000261 m^3

mass of fluid displaced = .000261*830
= .217 kg

mass metal - mass fluid displaced = 1.82 kg metal mass

metal weight = m g = 1.82*9.81 = 17.9 Newtons

Answer 2

Not helpful

Answer 3

TO ANSWER QUESTION DIRECTLY

Answer 4

2.12