A man drops a rock off the side of a cliff, and hears it hit the bottom 2.8 seconds later. If the average speed of sound is 335 m/s, how high is the cliff?
I have been able to figure out this much, but I don't know how to solve the problem with the data that I have been given. I do not need an answer, I simply wish to understand the problem. Assume that there is no air resistance.
Rock: Vi=0m/s Vf=? a=9.81m/s(squared) traveled the same distance as sound.
Speed of sound: V=335m/s distance traveled = distance rock traveled.
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time for rock to fall plus time for sound to travel to him equals 2.8s.solve both.add them and solve for H
1 answer