(c) solve for t in
h(t) = 10 + 15t - 4.9t^2 = 0
that same function will allow you to answer the other questions.
25. Maria is standing at the edge of a cliff that is 10 m high over a canyon. She throws a rock upward off the side of the cliff. Right before the rock reaches the canyon floor, it has a speed of 25 m/s.
a) What was the rock’s total displacement? 10 meters
b) What was the initial velocity of the rock?
c) What was the total trip time?
d) What was the maximum height above the canyon floor reached by the rock?
2 answers
sorry. don't know where the 15 came from.
If the initial upward velocity was v, then we have
10 + vt - 4.9t^2 = 0
use that value of t in the velocity function
v - 9.8t = -25
to find the initial velocity
max height is at the vertex of the parabola, achieved at t=v/9.8
If the initial upward velocity was v, then we have
10 + vt - 4.9t^2 = 0
use that value of t in the velocity function
v - 9.8t = -25
to find the initial velocity
max height is at the vertex of the parabola, achieved at t=v/9.8
5 answers