A machine has a VR of 6 and is 80%efficiency what effort would be needed to lift a load of 300N with aid of this machine [62.5N

1 answer

To determine the effort required to lift a load using a machine with a certain velocity ratio (VR) and efficiency, we can use the following formula:

\[ \text{Effort} = \frac{\text{Load}}{\text{Efficiency} \times \text{VR}} \]

In this case, we have:

  • Load (\(L\)) = 300 N
  • Efficiency (\(η\)) = 80% = 0.80
  • Velocity Ratio (\(VR\)) = 6

Substituting these values into the formula gives:

\[ \text{Effort} = \frac{300 , \text{N}}{0.80 \times 6} \]

Calculating the denominator:

\[ 0.80 \times 6 = 4.8 \]

Now substituting back into the equation:

\[ \text{Effort} = \frac{300 , \text{N}}{4.8} \]

Calculating the effort:

\[ \text{Effort} = 62.5 , \text{N} \]

Thus, the effort needed to lift a load of 300 N with the aid of this machine is indeed 62.5 N.