A machine has a velocity ratio of 6and an efficiency of 80 efficiency calculate the effort needed to raise a load of 90N

Answer 1

Efficiency is calculated using the formula: efficiency = (output work / input work) * 100

Since the machine has an efficiency of 80%, we can set up the equation as follows:
80 = (output work / input work) * 100

To find the effort needed, we can rearrange the equation:
output work / input work = 80 / 100

Simplifying the equation:
output work / input work = 0.8

The velocity ratio of the machine is 6. This means that for every 1 unit of input distance, the machine moves the load 6 units of output distance.

We can use the formula for velocity ratio: velocity ratio = output distance / input distance

To find the input distance, we can rearrange the equation:
input distance = output distance / velocity ratio

Since the output distance is the input distance multiplied by the velocity ratio, we can substitute this into the efficiency equation as follows:

(output work / (output distance / velocity ratio)) = 0.8

Simplifying the equation:
(output work * velocity ratio) / output distance = 0.8

Given that the load is 90N, we can substitute this into the equation as the output work and 90 / output distance is equal to the load.

(90 * velocity ratio) / output distance = 0.8

Substituting the velocity ratio of 6, we get:

(90 * 6) / output distance = 0.8

540 / output distance = 0.8

To find the output distance, we can rearrange the equation:
output distance = 540 / 0.8

Simplifying the equation:
output distance = 675

Now that we have the output distance, we can use the velocity ratio to find the input distance:

input distance = output distance / velocity ratio
input distance = 675 / 6
input distance = 112.5

The effort needed to raise a load of 90N is equal to the input force. Since force = load / velocity ratio, we can calculate the effort as follows:

effort = load / velocity ratio
effort = 90 / 6
effort = 15N

Therefore, the effort needed to raise a load of 90N is 15N.