A machine has a velocity ratio of 6 and is 80% efficiency.what effort would be needed to lift of 300N with the aid of this machine?

Answer 1

To find the effort needed to lift a load of 300 N with a machine that has a velocity ratio of 6 and an efficiency of 80%, we can use the formula:

\[ \text{Effort} = \frac{\text{Load}}{\text{Mechanical Advantage}} \]

Where:

• Mechanical Advantage (MA) can be calculated using the formula:

\[ \text{Mechanical Advantage} = \text{Velocity Ratio} \times \text{Efficiency} \]

First, we need to express the efficiency as a decimal.

• Efficiency = 80% = 0.80

Now, we can calculate the Mechanical Advantage:

\[ \text{Mechanical Advantage} = 6 \times 0.80 = 4.8 \]

Next, we can calculate the effort required:

\[ \text{Effort} = \frac{\text{Load}}{\text{Mechanical Advantage}} = \frac{300, \text{N}}{4.8} \]

Now performing the calculation:

\[ \text{Effort} = \frac{300}{4.8} \approx 62.5 , \text{N} \]

Therefore, the effort needed to lift a load of 300 N with this machine is approximately 62.5 N.