slope of the line:
m=(-3-1)/(4+1)=-4/5
slope of the perpendicular (gradient)=5/4
A is the point (4,-3) and b is (-1,1). Find the gradient of a line perpendicular to AB. Plz help!!!!
2 answers
use y=mx+c
now x1=4 and x2=-1
y1=-3 and y2=1
x1=4&y1=-3
sub into equation of the line
-3=m*4+c
4m+c=-3...(1)
now x2 and y2
1=-m+c
-m+c=1...(2)
subtract 2 from 1
5m=-3
m=-4/5
when perpendicular it is now 5/4
now x1=4 and x2=-1
y1=-3 and y2=1
x1=4&y1=-3
sub into equation of the line
-3=m*4+c
4m+c=-3...(1)
now x2 and y2
1=-m+c
-m+c=1...(2)
subtract 2 from 1
5m=-3
m=-4/5
when perpendicular it is now 5/4
1 answer