the force is proportional to the square of the diameter
w = (30 / 4.5)^2 * 500 N
a hydrauli press has a ram of 30 cm diameter and plunger of 4.5cm diameter. find the the weight lifted by the hydraulic press when the force applied at the plunger is 500N
5 answers
i want answer
F/a=w/A
W=FA/a
W=500*(30^2)/(4.5^2)
W=22222.22N
W=22.22KN
W=FA/a
W=500*(30^2)/(4.5^2)
W=22222.22N
W=22.22KN
the answer of the questions
7. A hydraulic press has a ram of 35 cm diameter and a plunger of 5 cm diameter. It is used for lifting a weight of 30KN. Find the force required at the plunger in kN.
3 answers