A hydraulic plunger has a 12 cm diameter and a force of 350 kN acts on it. What is the pressure exerted on the plunger?

Answer 1

r = 0.06 meters
A = pi r^2

F = 350,000 Newtons

p = F/A = 350,000 /(pi *.06^2)
in Newtons per square meter which is Pascals