To get the answer of 27m
You would need to add the D1x and D2x together. And the same for D1y and D2y. But since the dys are in opposite direction, u subtract.
Drx=5.9(n)+18.4(e)=24.3(e)
Dry=26.2(s)-13.8(n)=12.4 (s)
A horse runs 15 m [N 23° E] and then 32 m [S 35° E]. What is the total displacement of the horse?
I can't even visualise this...
My friend told me the basic steps on how to solve it, but I got the wrong answer anyways...
d1 = 15 m [N 23° E]
d1x = 15m sin 23°
= 5.9 m
d1y = 15 m cos 23°
= 13.8 m
d2 = 32 m [S 35° E]
d2x=32m sin 35°
= 18.35 m
d2y = 32 m cos 35°
= 26.2 m
dR = d1 + d2
dRx = d1x + d1y = 5.9 m + 13.8 m = 19.7 m
dRy = d2x + d2y = 18.35 + 26.2 = 44.5 m
|dR| = sqrt 44.5 m^2 + 19.7 m^2
= 49 m
Theta = tan^-1 (44.5 m/21.3m)
= 64.4 m
Therefore dR = 49 m [and I don't even know what units would go in the square brackets...]
The answer is 27 m [E 27° S]
I know you can use cosine law/sine law but for me I need to visualise it in order to use cosine and sine law but I can't even sketch this properly, so...
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