Asked by shan
A horse runs off of a 11 meter high cliff into the sea. The horse is running at a speed of 3.6 m/s. How much time does the horse spend in the air? How far from the base of the cliff is the horse when it hits the water?
Answers
Answered by
drwls
Time in the air is given by:
(1/2) g T^2 = 11 m
V * T = horizontal distance traveled
(1/2) g T^2 = 11 m
V * T = horizontal distance traveled
Answered by
bobpursley
First, how long in the air?
h=1/2 g t^2 solve for t.
How far away horizontally?
d=rt
d=3.6m/s * time
h=1/2 g t^2 solve for t.
How far away horizontally?
d=rt
d=3.6m/s * time
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