distance west = 3.5 cos 55 - 2.7 sin 16 = a
distance south = 3.5 sin 55 + 2.7 cos 16 = b
displacement = sqrt (a^2+b^2)
tan angle S of W = b/a
A hiker leaves her camp and walks 3.5 km in a direction of 55° south of west to the lake. After a short rest at the lake, she hikes 2.7 km in a direction of 16° east of south to the scenic overlook.
What is the magnitude of the hiker’s resultant displacement? Round your answer to the nearest tenth.
km
What is the direction of the hiker’s resultant displacement? Round your answer to nearest whole degree.
° south of west
4 answers
isk
deez nuts west = 3.5 coc 55 - 2.7 sin 16 = a
distance mouth = 36969695 sin 55 +696969 = b
deez nuts = sqrt (a^2+b^2)
tan angle S of W = b/a
distance mouth = 36969695 sin 55 +696969 = b
deez nuts = sqrt (a^2+b^2)
tan angle S of W = b/a
5.6
77
77
2 answers