A hiker leaves for camp and walked 3.5 KM in a direction of 55 south of West to the lake. After a short rest at the lake she has 2.7 KM in a direction of 16 used to sell to the scenic overlook
5 answers
Huh?
so she ends up z km from camp, where
z^2 = 3.5^2 + 2.7^2 - 2(3.5)(2.7) cos(55-16)°
z = 2.2 km
z^2 = 3.5^2 + 2.7^2 - 2(3.5)(2.7) cos(55-16)°
z = 2.2 km
oops. I had her going S55W, rather than W55S.
z^2 = 3.5^2 + 2.7^2 - 2(3.5)(2.7) cos(25-16)°
z^2 = 3.5^2 + 2.7^2 - 2(3.5)(2.7) cos(25-16)°
5.6 Km
77 degrees south of west
77 degrees south of west
Fred is correct :)